# Line slope calculator 2x-5y=-28

**Straight line given by points A[1; 6] and B[6; 8]**

## Calculation:

**Slope-intercept form of line:**y = 0.4x+5.6

**Canonical form of the line equation:**2x-5y+28 = 0

**Parametric form of the line equation:**

x = 5t+1

y = 2t+6 ; t ∈ R

**Slope:**m = 0.4

**Slope angle of line: φ =**21°48'5″ = 0.3805 rad

**X intercept:**x

_{0}= -14

**Y intercept:**y

_{0}= q = 5.6

**Distance line from the origin:**d

_{0}= 5.1995

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; 2)

**Normal vector: n =**(2; -5)

**Midpoint of the segment AB: M =**[3.5; 7]

**Perpendicular Bisector equation:**5x+2y-31.5 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (6; 8) ; |OB| = 10**

**Scalar product OA .OB = 54**

**Angle ∠ AOB = 27°24'27″ = 0.4784 rad**